9.2: Simplify Square Roots (2024)

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    Learning Objectives

    By the end of this section, you will be able to:

    • Use the Product Property to simplify square roots
    • Use the Quotient Property to simplify square roots
    BE PREPARED

    Before you get started take this readiness quiz.

    1. Simplify: \(\frac{80}{176}\).
      If you missed this problem, review [link].
    2. Simplify: \(\frac{n^9}{n^3}\).
      If you missed this problem, review [link].
    3. Simplify: \(\frac{q^4}{q^{12}}\).
      If you missed this problem, review [link].

      In the last section, we estimated the square root of a number between two consecutive whole numbers. We can say that \(\sqrt{50}\) is between 7 and 8. This is fairly easy to do when the numbers are small enough that we can use [link].

      But what if we want to estimate \(\sqrt{500}\)? If we simplify the square root first, we’ll be able to estimate it easily. There are other reasons, too, to simplify square roots as you’ll see later in this chapter.

      A square root is considered simplified if its radicand contains no perfect square factors.

      Definition: SIMPLIFIED SQUARE ROOT

      \(\sqrt{a}\) is considered simplified if a has no perfect square factors.

      So \(\sqrt{31}\) is simplified. But \(\sqrt{32}\) is not simplified, because 16 is a perfect square factor of 32.

      Use the Product Property to Simplify Square Roots

      The properties we will use to simplify expressions with square roots are similar to the properties of exponents. We know that \((ab)^m=a^{m}b^{m}\). The corresponding property of square roots says that \(\sqrt{ab}=\sqrt{a}·\sqrt{b}\).

      Definition: PRODUCT PROPERTY OF SQUARE ROOTS

      If a, b are non-negative real numbers, then \(\sqrt{ab}=\sqrt{a}·\sqrt{b}\).

      We use the Product Property of Square Roots to remove all perfect square factors from a radical. We will show how to do this in Example.

      How To Use the Product Property to Simplify a Square Root

      Example \(\PageIndex{1}\)

      Simplify: \(\sqrt{50}\).

      Answer

      9.2: Simplify Square Roots (2)9.2: Simplify Square Roots (3)9.2: Simplify Square Roots (4)

      Example \(\PageIndex{2}\)

      Simplify: \(\sqrt{48}\).

      Answer

      \(4\sqrt{3}\)

      Example \(\PageIndex{3}\)

      Simplify: \(\sqrt{45}\).

      Answer

      \(3\sqrt{5}\)

      Notice in the previous example that the simplified form of \(\sqrt{50}\) is \(5\sqrt{2}\), which is the product of an integer and a square root. We always write the integer in front of the square root.

      Definition: SIMPLIFY A SQUARE ROOT USING THE PRODUCT PROPERTY.
      1. Find the largest perfect square factor of the radicand. Rewrite the radicand as a product using the perfect-square factor.
      2. Use the product rule to rewrite the radical as the product of two radicals.
      3. Simplify the square root of the perfect square.
      Example \(\PageIndex{4}\)

      Simplify: \(\sqrt{500}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{500}}\\ {\text{Rewrite the radicand as a product using the largest perfect square factor}}&{\sqrt{100·5}}\\ {\text{Rewrite the radical as the product of two radicals}}&{\sqrt{100}·\sqrt{5}}\\ {\text{Simplify}}&{10\sqrt{5}}\\ \end{array}\]

      Example \(\PageIndex{6}\)

      Simplify:\(\sqrt{432}\).

      Answer

      \(12\sqrt{3}\)

      We could use the simplified form \(10\sqrt{5}\) to estimate \(\sqrt{500}\). We know \(\sqrt{5}\) is between 2 and 3, and \(\sqrt{500}\) is \(10\sqrt{5}\). So \(\sqrt{500}\) is between 20 and 30.

      The next example is much like the previous examples, but with variables.

      Example \(\PageIndex{7}\)

      Simplify: \(\sqrt{x^3}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{x^3}}\\ {\text{Rewrite the radicand as a product using the largest perfect square factor}}&{\sqrt{x^2·x}}\\ {\text{Rewrite the radical as the product of two radicals}}&{\sqrt{x^2}·\sqrt{x}}\\ {\text{Simplify}}&{x\sqrt{x}}\\ \end{array}\]

      Example \(\PageIndex{8}\)

      Simplify:\(\sqrt{b^5}\).

      Answer

      \(b^2\sqrt{b}\)

      Example \(\PageIndex{9}\)

      Simplify: \(\sqrt{p^9}\).

      Answer

      \(p^4\sqrt{p}\)

      We follow the same procedure when there is a coefficient in the radical, too.

      Example \(\PageIndex{10}\)

      Simplify: \(\sqrt{25y^5}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{25y^5}}\\ {\text{Rewrite the radicand as a product using the largest perfect square factor.}}&{\sqrt{25y^4·y}}\\ {\text{Rewrite the radical as the product of two radicals.}}&{\sqrt{25y^4}·\sqrt{y}}\\ {\text{Simplify.}}&{5y^2\sqrt{y}}\\ \end{array}\]

      Example \(\PageIndex{11}\)

      Simplify: \(\sqrt{16x^7}\).

      Answer

      \(4x^3\sqrt{x}\)

      Example \(\PageIndex{12}\)

      Simplify: \(\sqrt{49v^9}\).

      Answer

      \(7v^4\sqrt{v}\)

      In the next example both the constant and the variable have perfect square factors.

      Example \(\PageIndex{13}\)

      Simplify: \(\sqrt{72n^7}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{72n^7}}\\ {\text{Rewrite the radicand as a product using the largest perfect square factor.}}&{\sqrt{36n^{6}·2n}}\\ {\text{Rewrite the radical as the product of two radicals.}}&{\sqrt{36n^{6}}·\sqrt{2n}}\\ {\text{Simplify.}}&{6n^3\sqrt{2n}}\\ \end{array}\]

      Example \(\PageIndex{14}\)

      Simplify: \(\sqrt{32y^5}\).

      Answer

      \(4y^2\sqrt{2y}\)

      Example \(\PageIndex{15}\)

      Simplify: \(\sqrt{75a^9}\).

      Answer

      \(5a^4\sqrt{3a}\)

      Example \(\PageIndex{16}\)

      Simplify: \(\sqrt{63u^{3}v^{5}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{63u^{3}v^{5}}}\\ {\text{Rewrite the radicand as a product using the largest perfect square factor.}}&{\sqrt{9u^{2}v^{4}·7uv}}\\ {\text{Rewrite the radical as the product of two radicals.}}&{\sqrt{9u^{2}v^{4}}·\sqrt{7uv}}\\ {\text{Simplify.}}&{3uv^{2}\sqrt{7uv}}\\ \end{array}\]

      Example \(\PageIndex{17}\)

      Simplify: \(\sqrt{98a^{7}b^{5}}\).

      Answer

      \(7a^{3}b^{2}\sqrt{2ab}\)

      Example \(\PageIndex{18}\)

      Simplify: \(\sqrt{180m^{9}n^{11}}\).

      Answer

      \(6m^{4}n^{5}\sqrt{5mn}\)

      We have seen how to use the Order of Operations to simplify some expressions with radicals. To simplify \(\sqrt{25}+\sqrt{144}\) we must simplify each square root separately first, then add to get the sum of 17.

      The expression \(\sqrt{17}+\sqrt{7}\) cannot be simplified—to begin we’d need to simplify each square root, but neither 17 nor 7 contains a perfect square factor.

      In the next example, we have the sum of an integer and a square root. We simplify the square root but cannot add the resulting expression to the integer.

      Example \(\PageIndex{19}\)

      Simplify: \(3+\sqrt{32}\).

      Answer

      \[\begin{array}{ll} {}&{3+\sqrt{32}}\\ {\text{Rewrite the radicand as a product using the largest perfect square factor.}}&{3+\sqrt{16·2}}\\ {\text{Rewrite the radical as the product of two radicals.}}&{3+\sqrt{16}·\sqrt{2}}\\ {\text{Simplify.}}&{3+4\sqrt{2}}\\ \end{array}\]

      The terms are not like and so we cannot add them. Trying to add an integer and a radical is like trying to add an integer and a variable—they are not like terms!

      Example \(\PageIndex{20}\)

      Simplify: \(5+\sqrt{75}\).

      Answer

      \(5+5\sqrt{3}\)

      Example \(\PageIndex{21}\)

      Simplify: \(2+\sqrt{98}\).

      Answer

      \(2+7\sqrt{2}\)

      The next example includes a fraction with a radical in the numerator. Remember that in order to simplify a fraction you need a common factor in the numerator and denominator.

      Example \(\PageIndex{22}\)

      Simplify: \(\frac{4−\sqrt{48}}{2}\).

      Answer

      \[\begin{array}{ll} {}&{\frac{4−\sqrt{48}}{2}}\\ {\text{Rewrite the radicand as a product using thelargest perfect square factor.}}&{\frac{4−\sqrt{16·3}}{2}}\\ {\text{Rewrite the radical as the product of two radicals.}}&{\frac{4−\sqrt{16}·\sqrt{3}}{2}}\\ {\text{Simplify.}}&{\frac{4−4\sqrt{3}}{2}}\\ {\text{Factor the common factor from thenumerator.}}&{\frac{4(1−\sqrt{3})}{2}}\\ {\text{Remove the common factor, 2, from thenumerator and denominator.}}&{2(1−\sqrt{3})}\\ \end{array}\]

      Example \(\PageIndex{23}\)

      Simplify: \(\frac{10−\sqrt{75}}{5}\).

      Answer

      \(2−\sqrt{3}\)

      Example \(\PageIndex{24}\)

      Simplify: \(\frac{6−\sqrt{45}}{3}\).

      Answer

      \(2−\sqrt{5}\)

      Use the Quotient Property to Simplify Square Roots

      Whenever you have to simplify a square root, the first step you should take is to determine whether the radicand is a perfect square. A perfect square fraction is a fraction in which both the numerator and the denominator are perfect squares.

      Example \(\PageIndex{25}\)

      Simplify: \(\sqrt{\frac{9}{64}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{\frac{9}{64}}}\\ {\text{Since} (\frac{3}{8})^2}&{\frac{3}{8}}\\ \end{array}\]

      Example \(\PageIndex{26}\)

      Simplify: \(\sqrt{\frac{25}{16}}\).

      Answer

      \(\frac{5}{4}\)

      Example \(\PageIndex{27}\)

      Simplify: \(\sqrt{\frac{49}{81}}\).

      Answer

      \(\frac{7}{9}\)

      If the numerator and denominator have any common factors, remove them. You may find a perfect square fraction!

      Example \(\PageIndex{28}\)

      Simplify: \(\sqrt{\frac{45}{80}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{\frac{45}{80}}}\\ {\text{Simplify inside the radical first. Rewrite showing the common factors of the numerator and denominator.}}&{\sqrt{\frac{5·9}{5·16}}}\\ {\text{Simplify the fraction by removing common factors.}}&{\sqrt{\frac{9}{16}}}\\ {\text{Simplify.} (\frac{3}{4})^2 =\frac{9}{16}}&{\frac{3}{4}}\\ \end{array}\]

      Example \(\PageIndex{29}\)

      Simplify: \(\sqrt{\frac{75}{48}}\).

      Answer

      \(\frac{5}{4}\)

      Example \(\PageIndex{30}\)

      Simplify: \(\sqrt{\frac{98}{162}}\).

      Answer

      \(\frac{7}{9}\)

      In the last example, our first step was to simplify the fraction under the radical by removing common factors. In the next example we will use the Quotient Property to simplify under the radical. We divide the like bases by subtracting their exponents, \(\frac{a^m}{a^n} = a^{m-n}\), \(a \ne 0\).

      Example \(\PageIndex{31}\)

      Simplify: \(\sqrt{\frac{m^6}{m^4}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{\frac{m^6}{m^4}}}\\ {\text{Simplify the fraction inside the radical first}}&{}\\ {}&{\sqrt{m^2}}\\ {\text{Divide the like bases by subtracting the exponents.}}&{}\\ {\text{Simplify.}}&{m}\\ \end{array}\]

      Example \(\PageIndex{32}\)

      Simplify: \(\sqrt{\frac{a^8}{a^6}}\).

      Answer

      a

      Example \(\PageIndex{33}\)

      Simplify: \(\sqrt{\frac{x^{14}}{x^{10}}}\).

      Answer

      \(x^2\)

      Example \(\PageIndex{34}\)

      Simplify: \(\sqrt{\frac{48p^7}{3p^3}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{\frac{48p^7}{3p^3}}}\\ {\text{Simplify the fraction inside the radical first.}}&{\sqrt{16p^4}}\\ {\text{Simplify.}}&{4p^2}\\ \end{array}\]

      Example \(\PageIndex{35}\)

      Simplify: \(\sqrt{\frac{75x^5}{3x}}\).

      Answer

      \(5x^2\)

      Example \(\PageIndex{36}\)

      Simplify: \(\sqrt{\frac{72z^{12}}{2z^{10}}}\).

      Answer

      6z

      Remember the Quotient to a Power Property? It said we could raise a fraction to a power by raising the numerator and denominator to the power separately.

      \((\frac{a}{b})^m=\frac{a^{m}}{b^{m}}\), \( b \ne 0\)

      We can use a similar property to simplify a square root of a fraction. After removing all common factors from the numerator and denominator, if the fraction is not a perfect square we simplify the numerator and denominator separately.

      Definition: QUOTIENT PROPERTY OF SQUARE ROOTS

      If a, b are non-negative real numbers and \(b \ne 0\), then

      \(\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)

      Example \(\PageIndex{37}\)

      Simplify: \(\sqrt{\frac{21}{64}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{\frac{21}{64}}}\\ {\text{We cannot simplify the fraction inside the radical. Rewrite using the quotient property.}}&{\frac{\sqrt{21}}{\sqrt{64}}}\\ {\text{Simplify the square root of 64. The numerator cannot be simplified.}}&{\frac{\sqrt{21}}{8}}\\ \end{array}\]

      Example \(\PageIndex{38}\)

      Simplify: \(\sqrt{\frac{19}{49}}\).

      Answer

      \(\frac{\sqrt{19}}{7}\)

      Example \(\PageIndex{39}\)

      Simplify:\(\sqrt{\frac{28}{81}}\)

      Answer

      \(\frac{2\sqrt{7}}{9}\)

      How to Use the Quotient Property to Simplify a Square Root

      Example \(\PageIndex{40}\)

      Simplify: \(\sqrt{\frac{27m^3}{196}}\).

      Answer

      9.2: Simplify Square Roots (5)9.2: Simplify Square Roots (6)9.2: Simplify Square Roots (7)

      Example \(\PageIndex{41}\)

      Simplify: \(\sqrt{\frac{24p^3}{49}}\)

      Answer

      \(\frac{2p\sqrt{6p}}{7}\)

      Example \(\PageIndex{42}\)

      Simplify: \(\sqrt{\frac{48x^5}{100}}\)

      Answer

      \(\frac{2x^2\sqrt{3x}}{5}\)

      Definition: SIMPLIFY A SQUARE ROOT USING THE QUOTIENT PROPERTY.
      1. Simplify the fraction in the radicand, if possible.
      2. Use the Quotient Property to rewrite the radical as the quotient of two radicals.
      3. Simplify the radicals in the numerator and the denominator.
      Example \(\PageIndex{43}\)

      Simplify: \(\sqrt{\frac{45x^5}{y^4}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{\frac{45x^5}{y^4}}}\\ {\text{We cannot simplify the fraction inside the radical. Rewrite using the quotient property.}}&{\frac{\sqrt{45x^5}}{\sqrt{y^4}}}\\ {\text{Simplify the radicals in the numerator and the denominator.}}&{\frac{\sqrt{9x^4}\sqrt{5x}}{y^2}}\\ {\text{Simplify.}}&{\frac{3x^2\sqrt{5x}}{y^2}}\\ \end{array}\]

      Example \(\PageIndex{44}\)

      Simplify: \(\sqrt{\frac{80m^3}{n^6}}\)

      Answer

      \(\frac{4m\sqrt{5m}}{n^3}\)

      Example \(\PageIndex{45}\)

      Simplify: \(\sqrt{\frac{54u^7}{v^8}}\).

      Answer

      \(\frac{3u^3\sqrt{6u}}{v^4}\)

      Be sure to simplify the fraction in the radicand first, if possible.

      Example \(\PageIndex{46}\)

      Simplify: \(\sqrt{\frac{81d^9}{25d^4}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{\frac{81d^9}{25d^4}}}\\ {\text{Simplify the fraction in the radicand.}}&{\sqrt{\frac{81d^5}{25}}}\\ {\text{Rewrite using the quotient property.}}&{\frac{\sqrt{81d^5}}{\sqrt{25}}}\\ {\text{Simplify the radicals in the numerator and the denominator.}}&{\frac{\sqrt{81d^4}\sqrt{d}}{5}}\\ {\text{Simplify.}}&{\frac{9d^2\sqrt{d}}{5}}\\ \end{array}\]

      Example \(\PageIndex{47}\)

      Simplify: \(\sqrt{\frac{64x^7}{9x^3}}\).

      Answer

      \(\frac{8x^2}{3}\)

      Example \(\PageIndex{48}\)

      Simplify: \(\sqrt{\frac{16a^9}{100a^5}}\).

      Answer

      \(\frac{2a^2}{5}\)

      Example \(\PageIndex{49}\)

      Simplify: \(\sqrt{\frac{18p^5q^7}{32pq^2}}\).

      Answer

      \[\begin{array}{ll} {}&{\sqrt{\frac{18p^5q^7}{32pq^2}}}\\ {\text{Simplify the fraction in the radicand.}}&{\sqrt{\frac{9p^4q^5}{16}}}\\ {\text{Rewrite using the quotient property.}}&{\frac{\sqrt{9p^4q^5}}{\sqrt{16}}}\\ {\text{Simplify the radicals in the numerator and the denominator.}}&{\frac{\sqrt{9p^4q^4}\sqrt{q}}{4}}\\ {\text{Simplify.}}&{\frac{3p^2q^2\sqrt{q}}{4}}\\ \end{array}\]

      ExAMPLe \(\PageIndex{50}\)

      Simplify: \(\sqrt{\frac{50x^5y^3}{72x^4y}}\).

      Answer

      \(\frac{5y\sqrt{x}}{6}\)

      Example \(\PageIndex{51}\)

      Simplify: \(\sqrt{\frac{48m^7n^2}{125m^5n^9}}\).

      Answer

      \(\frac{4m\sqrt{3}}{5n^3\sqrt{5n}}\)

      Key Concepts

      • Simplified Square Root \(\sqrt{a}\) is considered simplified if a has no perfect-square factors.
      • Product Property of Square Roots If a, b are non-negative real numbers, then

        \(\sqrt{ab}=\sqrt{a}·\sqrt{b}\)

      • Simplify a Square Root Using the Product Property To simplify a square root using the Product Property:
        1. Find the largest perfect square factor of the radicand. Rewrite the radicand as a product using the perfect square factor.
        2. Use the product rule to rewrite the radical as the product of two radicals.
        3. Simplify the square root of the perfect square.
      • Quotient Property of Square Roots If a, b are non-negative real numbers and \(b \ne 0\), then

        \(\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\)

      • Simplify a Square Root Using the Quotient Property To simplify a square root using the Quotient Property:
        1. Simplify the fraction in the radicand, if possible.
        2. Use the Quotient Rule to rewrite the radical as the quotient of two radicals.
        3. Simplify the radicals in the numerator and the denominator.
      9.2: Simplify Square Roots (2024)

      FAQs

      What are the square roots of 9? ›

      The square root of 9 is equal to 3. It is represented as √9 in radical form and 91/2 in exponential form.

      How to simplify square roots? ›

      Step 1: Find the prime factors of the number inside the radical sign. Step 2: Group the factors into pairs. Step 3: Pull out one integer outside the radical sign for each pair. Leave the other integers that could not be paired inside the radical sign.

      Does 9 have two square roots? ›

      Important Notes on Square Root of 9:

      The square root of 9 is 3 and -3.

      What is the square root of 9 between? ›

      Short answer: 3. And sometimes also -3. Medium answer: If you mean “what is the principal square root of 9?”, then the answer is 3. If you mean “what number can I square to get 9?”, then there are two answers: 3 and -3.

      How to calculate the square of 9? ›

      Squaring a number means multiplying it by itself once. So, to find the square of 9, you do 9 x 9 = 81.

      Is √9 real? ›

      Explanation: It is rational,natural, whole, integer and real.

      What kind of number is √9? ›

      In mathematics, a rational number is a number that can be expressed as the quotient or fractionpq of two integers, a numerator p and a non-zero denominator q. Now √9=3=31=62=93 9 = 3 = 3 1 = 6 2 = 9 3 and so on. Where both numerator and denominator are positive integers. So, we can say that √9 is a rational number.

      Can you simplify adding square roots? ›

      If the bases are not the same, then the square roots cannot be directly added together. But, sometimes the terms can be simplified, allowing them to be added together.

      Why is 9 a square? ›

      In mathematics, a square number or perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, 9 is a square number, since it equals 32 and can be written as 3 × 3.

      How many roots does 9 have? ›

      3 and -3 are said to be the square roots of 9. A square root is written with a radical symbol √ and the number or expression inside the radical symbol, below denoted a, is called the radicand.

      What is the correct method to get the square root of 9? ›

      Square Root of 9 using Long Division Method

      As we have a single number in this case, therefore, we take the number 9. Step 2: Now, we need to find a number such that the number when multiplied by itself gives a value 9. So, the required number is 3, as 3×3 gives 9. Therefore, the square root of 9 is 3.

      How to simplify the cube root of 9? ›

      The cube root of 9 is the number which when multiplied by itself three times gives the product as 9. Since 9 can be expressed as 3 × 3. Therefore, the cube root of 9 = ∛(3 × 3) = 2.0801.

      What is the square root of 9 natural number? ›

      The square root of 9 is equal to 3 or -3 because 3*3=9 and (-3)*(-3)=9. 3 belong to the N set, the Natural numbers Set because it is greater than zero(that means 3 is positive)and it has no figure after the decimal point.

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      Name: Dong Thiel

      Birthday: 2001-07-14

      Address: 2865 Kasha Unions, West Corrinne, AK 05708-1071

      Phone: +3512198379449

      Job: Design Planner

      Hobby: Graffiti, Foreign language learning, Gambling, Metalworking, Rowing, Sculling, Sewing

      Introduction: My name is Dong Thiel, I am a brainy, happy, tasty, lively, splendid, talented, cooperative person who loves writing and wants to share my knowledge and understanding with you.